Decide if the function is an exponential growth function or exponential decay function, and describe its end behavior using limits. y=0.8^x

Answer:The answer is (d)Exponential decay function[tex]\lim_{x \to -\infty} f_x=0[/tex][tex]\lim_{x \to \infty} f_x= \infty[/tex]  Step-by-step explanation:∵ y = 0.8^x∵ 0.8 < 1 ∴ 0.8^x is decreasing ⇒ exponential decay functionEx: 0.8^-4 = 2.441 ⇒ 0.8^4 = 0.4096      when x increase the value of 0.8^x decrease[tex]\lim_{n \to -\infty} f_x=0.8^{-\infty} = \frac{1}{0.8^{\infty}}=0[/tex][tex]\lim_{x \to \infty} f_x=0.8^{\infty}=\infty[/tex] ∴ The answer is (d)